4/2x+5+x-7/4x^2-25

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Solution for 4/2x+5+x-7/4x^2-25 equation: 


x in (-oo:+oo)

(4/2)*x-((7/4)*x^2)+x-25+5 = 0

(-7/4)*x^2+(4/2)*x+x-25+5 = 0

3*x-7/4*x^2-20 = 0

DELTA = 3^2-(-20*(-7/4)*4)

DELTA = -131

DELTA < 0

x belongs to the empty set

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